1 # -*- coding: utf-8 -*-
2 ##############################################################################
4 # OpenERP, Open Source Management Solution
5 # Copyright (C) 2004-2010 Tiny SPRL (<http://tiny.be>).
7 # This program is free software: you can redistribute it and/or modify
8 # it under the terms of the GNU Affero General Public License as
9 # published by the Free Software Foundation, either version 3 of the
10 # License, or (at your option) any later version.
12 # This program is distributed in the hope that it will be useful,
13 # but WITHOUT ANY WARRANTY; without even the implied warranty of
14 # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
15 # GNU Affero General Public License for more details.
17 # You should have received a copy of the GNU Affero General Public License
18 # along with this program. If not, see <http://www.gnu.org/licenses/>.
20 ##############################################################################
22 from mx import DateTime
26 from osv import fields, osv
27 from tools.translate import _
29 class hr_employee_category(osv.osv):
30 _name = "hr.employee.category"
31 _description = "Employee Category"
34 'name' : fields.char("Category", size=64, required=True),
35 'parent_id': fields.many2one('hr.employee.category', 'Parent Category', select=True),
36 'child_ids': fields.one2many('hr.employee.category', 'parent_id', 'Child Categories')
39 def _check_recursion(self, cr, uid, ids):
42 cr.execute('select distinct parent_id from hr_employee_category where id in ('+','.join(map(str, ids))+')')
43 ids = filter(None, map(lambda x:x[0], cr.fetchall()))
50 (_check_recursion, 'Error ! You cannot create recursive Categories.', ['parent_id'])
53 hr_employee_category()
55 class hr_employee(osv.osv):
57 _description = "Employee"
58 _inherits = {'resource.resource':"resource_id"}
60 'country_id' : fields.many2one('res.country', 'Nationality'),
61 'birthday' : fields.date("Birthday"),
62 'ssnid': fields.char('SSN No', size=32, help='Social Security Number'),
63 'sinid': fields.char('SIN No', size=32),
64 'otherid': fields.char('Other ID', size=32),
65 'gender': fields.selection([('',''),('male','Male'),('female','Female')], 'Gender'),
66 'marital': fields.selection([('married','Married'),('unmarried','Unmarried'),('divorced','Divorced'),('other','Other')],'Marital Status', size=32),
68 'address_id': fields.many2one('res.partner.address', 'Working Address'),
69 'address_home_id': fields.many2one('res.partner.address', 'Home Address'),
70 'work_phone': fields.related('address_id', 'phone', type='char', string='Work Phone'),
71 'work_email': fields.related('address_id', 'email', type='char', string='Work E-mail'),
72 'work_location': fields.char('Office Location', size=32),
74 'notes': fields.text('Notes'),
75 'parent_id': fields.many2one('hr.employee', 'Manager', select=True),
76 'category_id' : fields.many2one('hr.employee.category', 'Category'),
77 'child_ids': fields.one2many('hr.employee', 'parent_id','Subordinates'),
78 'resource_id': fields.many2one('resource.resource','Resource',ondelete='cascade'),
81 'active' : lambda *a: True,
84 def _check_recursion(self, cr, uid, ids):
87 cr.execute('select distinct parent_id from hr_employee where id in ('+','.join(map(str, ids))+')')
88 ids = filter(None, map(lambda x:x[0], cr.fetchall()))
95 (_check_recursion, 'Error ! You cannot create recursive Hierarchy of Employees.', ['parent_id'])
99 # vim:expandtab:smartindent:tabstop=4:softtabstop=4:shiftwidth=4: